a) \( \frac{1}{4} + \frac{1}{3} = \frac{1 \cdot 3 + 1 \cdot 4}{4 \cdot 3} = \frac{3+4}{12} = \frac{7}{12} \)
b) \( \frac{1}{2} - \frac{1}{9} = \frac{1 \cdot 9 - 1 \cdot 2}{2 \cdot 9} = \frac{9-2}{18} = \frac{7}{18} \)
c) \( \frac{3}{8} + \frac{1}{15} = \frac{3 \cdot 15 + 1 \cdot 8}{8 \cdot 15} = \frac{45+8}{120} = \frac{53}{120} \)
d) \( \frac{9}{10} - \frac{1}{30} = \frac{9 \cdot 3 - 1 \cdot 1}{30} = \frac{27-1}{30} = \frac{26}{30} = \frac{13}{15} \)
e) \( \frac{4}{15} + \frac{2}{45} = \frac{4 \cdot 3 + 2 \cdot 1}{45} = \frac{12+2}{45} = \frac{14}{45} \)
Ответы:
a) 7/12
b) 7/18
c) 53/120
d) 13/15
e) 14/45