Ответ:
Упростим корни: \(2\sqrt{12}=4\sqrt{3}\), \(\sqrt{27}=3\sqrt{3}\), \(\frac{1}{\sqrt{3}}=\frac{\sqrt{3}}{3}\).
\(2\sqrt{12}-\frac{1}{\sqrt{3}}+\sqrt{27}=4\sqrt{3}-\frac{\sqrt{3}}{3}+3\sqrt{3}=\frac{20\sqrt{3}}{3}\).
\(-\frac{3\sqrt{3}}{2}\cdot\frac{20\sqrt{3}}{3}=-30\).
Ответ: \(-30\)
