211.11-11.0,2. 15 19 19

$$2 \frac{11}{15} \cdot 1 \frac{1}{19} - 1 \frac{1}{19} \cdot 0,2 = \frac{2 \cdot 15 + 11}{15} \cdot \frac{1 \cdot 19 + 1}{19} - \frac{1 \cdot 19 + 1}{19} \cdot \frac{2}{10} = \frac{30 + 11}{15} \cdot \frac{19+1}{19} - \frac{19+1}{19} \cdot \frac{1}{5} = \frac{41}{15} \cdot \frac{20}{19} - \frac{20}{19} \cdot \frac{1}{5} = \frac{41}{15} \cdot \frac{20}{19} - \frac{20}{19 \cdot 5} = \frac{41 \cdot 4}{3 \cdot 19} - \frac{4}{19} = \frac{164}{57} - \frac{4}{19} = \frac{164}{57} - \frac{4 \cdot 3}{19 \cdot 3} = \frac{164}{57} - \frac{12}{57} = \frac{164 - 12}{57} = \frac{152}{57} = 2 \frac{38}{57} = 2 \frac{2 \cdot 19}{3 \cdot 19} = 2 \frac{2}{3} $$

Ответ: $$2 \frac{2}{3}$$