а) Здесь явно опечатка, т.к. вычитаемое больше уменьшаемого. Предполагаю, что задание \(2\frac{14}{19} - \frac{5}{19}\). Тогда \(2\frac{14}{19} - \frac{5}{19} = 2 \frac{14-5}{19} = 2 \frac{9}{19}\)
б) 8 \(\frac{7}{10}\) - 5 = 3 \(\frac{7}{10}\)
в) 12 - \(\frac{7}{18}\) = 11 + 1 - \(\frac{7}{18}\) = 11 + \(\frac{18}{18}\) - \(\frac{7}{18}\) = 11 \(\frac{18-7}{18}\) = 11 \(\frac{11}{18}\)
г) 11 - 3 \(\frac{5}{12}\) = 8 - \(\frac{5}{12}\) = 7 + 1 - \(\frac{5}{12}\) = 7 + \(\frac{12}{12}\) - \(\frac{5}{12}\) = 7 \(\frac{7}{12}\)
д) 8 \(\frac{7}{15}\) - 3 \(\frac{11}{15}\) = 5 \(\frac{7}{15}\) - \(\frac{11}{15}\) = 4 + 1 + \(\frac{7}{15}\) - \(\frac{11}{15}\) = 4 + \(\frac{15}{15}\) + \(\frac{7}{15}\) - \(\frac{11}{15}\) = 4 + \(\frac{22}{15}\) - \(\frac{11}{15}\) = 4 \(\frac{11}{15}\)
е) 10 \(\frac{9}{14}\) - 3 \(\frac{9}{14}\) = 7 \(\frac{9-9}{14}\) = 7 \(\frac{0}{14}\) = 7
Убрать каракули