Решение:
- \( \frac{7}{12} + \frac{3}{12} = \frac{7+3}{12} = \frac{10}{12} = \frac{5}{6} \)
- \( \frac{32}{39} - \frac{6}{39} = \frac{32-6}{39} = \frac{26}{39} = \frac{2}{3} \)
- \( 4 \frac{17}{45} + 3 \frac{13}{45} = (4+3) + \left( \frac{17}{45} + \frac{13}{45} \right) = 7 + \frac{17+13}{45} = 7 + \frac{30}{45} = 7 + \frac{2}{3} = 7 \frac{2}{3} \)
- \( 9 \frac{59}{63} - 5 \frac{24}{63} = (9-5) + \left( \frac{59}{63} - \frac{24}{63} \right) = 4 + \frac{59-24}{63} = 4 + \frac{35}{63} = 4 + \frac{5}{9} = 4 \frac{5}{9} \)
Ответ: 1) \( \frac{5}{6} \); 2) \( \frac{2}{3} \); 3) \( 7 \frac{2}{3} \); 4) \( 4 \frac{5}{9} \).