Ответ:
Проверим значения: \(\cos(\pi/6)=\sqrt{3}/2\), \(\cos(\pi)=-1\), \(\cos(\pi/4)=\sqrt{2}/2\), а \(\cos(3\pi/2)=0\).
Ответ: d) \(\cos(3\pi/2)\).
Проверим значения: \(\cos(\pi/6)=\sqrt{3}/2\), \(\cos(\pi)=-1\), \(\cos(\pi/4)=\sqrt{2}/2\), а \(\cos(3\pi/2)=0\).
Ответ: d) \(\cos(3\pi/2)\).