29) x^2 + x + 6 = -x^2 - 3x + (-2 + 2x^2)

Solution:

• Simplify the right side of the equation: \( -x^2 - 3x - 2 + 2x^2 = x^2 - 3x - 2 \)
• Set up the equation: \( x^2 + x + 6 = x^2 - 3x - 2 \)
• Subtract \( x^2 \) from both sides: \( x + 6 = -3x - 2 \)
• Add \( 3x \) to both sides: \( 4x + 6 = -2 \)
• Subtract 6 from both sides: \( 4x = -8 \)
• Divide by 4: \( x = -2 \)

Final Answer: x = -2