Давай упростим выражение, подставив b = 2.
(3a²b)³ = 3³ * (a²)³ * b³ = 27 * a⁶ * b³
\[ \frac{11a^6 b^3 - 27a^6 b^3}{4a^6 b^6} \]
11a⁶b³ - 27a⁶b³ = -16a⁶b³
\[ \frac{-16a^6 b^3}{4a^6 b^6} \]
\[ \frac{-16}{4} \times \frac{a^6}{a^6} \times \frac{b^3}{b^6} = -4 \times 1 \times \frac{1}{b^3} = -\frac{4}{b^3} \]
\[ -\frac{4}{2^3} = -\frac{4}{8} = -\frac{1}{2} \]
Ответ: -0.5