Ответ:
\[\left(\frac{4}{5}\right)^{-2}=\left(\frac{5}{4}\right)^2=\frac{25}{16},\quad \left(\frac{1}{27}\right)^{\frac{1}{3}}=\frac{1}{3},\quad 3,79^0=1.\]
Тогда
\[\frac{25}{16}-\frac{1}{3}+4=\frac{25}{16}+\frac{11}{3}=\frac{75+176}{48}=\frac{251}{48}.\]
Ответ: \(\frac{251}{48}\).
