Ответ:\(2y^3-2x^2y=2y(y^2-x^2)=2y(y-x)(y+x)\).\(x^2y+4yz^2-4xyz=y(x^2-4xz+4z^2)=y(x-2z)^2\).\(x-3+x^2(x-3)-2x(3-x)=(x-3)(1+x^2+2x)=(x-3)(x+1)^2\).\(4a^2+\frac43ab+\frac19b^2=\left(2a+\frac13b\right)^2\).