Ответ:

а) \(\frac4{11}+\left(\frac1{11}-6\right)\cdot\frac3{15}-\frac1{15}\)

\(=\frac4{11}+\left(-\frac{65}{11}\right)\cdot\frac15-\frac1{15}=\frac4{11}-\frac{13}{11}-\frac1{15}\)

\(=-\frac9{11}-\frac1{15}=-\frac{135+11}{165}=-\frac{146}{165}\).

б) \(\frac{16}{7}-\frac18=\frac{128-7}{56}=\frac{121}{56}=2\frac9{56}\).

в) \(\frac38+\frac56+1=\frac9{24}+\frac{20}{24}+\frac{24}{24}=\frac{53}{24}=2\frac5{24}\).

г) \(\frac9{12}+\frac34-\frac16=\frac34+\frac34-\frac16=\frac32-\frac16=\frac{9-1}{6}=\frac86=\frac43=1\frac13\).

д) \(\frac7{12}:\frac5{26}=\frac7{12}\cdot\frac{26}{5}=\frac{91}{30}=3\frac1{30}\).

е) \(\frac5{11}:\frac3{11}\cdot\frac35=\frac5{11}\cdot\frac{11}{3}\cdot\frac35=1\).

Ответ: а) \(-\frac{146}{165}\); б) \(2\frac9{56}\); в) \(2\frac5{24}\); г) \(1\frac13\); д) \(3\frac1{30}\); е) 1.