Ответ:
- НОК(9, 4) = 36: \(\frac59+\frac34=\frac{20}{36}+\frac{27}{36}=\frac{47}{36}=1\frac{11}{36}\).
- \(\frac3{20}=\frac9{60}\), поэтому \(\frac{19}{60}-\frac3{20}=\frac{19}{60}-\frac9{60}=\frac{10}{60}=\frac16\).
- НОК(44, 33) = 132: \(\frac{13}{44}-\frac7{33}=\frac{39}{132}-\frac{28}{132}=\frac{11}{132}=\frac1{12}\).
- НОК(150, 90) = 450: \(\frac{17}{150}-\frac1{90}=\frac{51}{450}-\frac5{450}=\frac{46}{450}=\frac{23}{225}\).
- НОК(5, 10, 12) = 60: \(\frac45+\frac7{10}-\frac5{12}=\frac{48}{60}+\frac{42}{60}-\frac{25}{60}=\frac{65}{60}=\frac{13}{12}=1\frac1{12}\).
- Сначала вычислим скобки: \(\frac34-\frac35=\frac{15}{20}-\frac{12}{20}=\frac3{20}\). Тогда \(\frac9{10}-\frac3{20}+\frac58=\frac{36}{40}-\frac6{40}+\frac{25}{40}=\frac{55}{40}=\frac{11}{8}=1\frac38\).
Ответ: 1) \(1\frac{11}{36}\); 2) \(\frac16\); 3) \(\frac1{12}\); 4) \(\frac{23}{225}\); 5) \(1\frac1{12}\); 6) \(1\frac38\).
