Ответ:
- \(3\sqrt{20}-\sqrt{5}=3\cdot2\sqrt{5}-\sqrt{5}=6\sqrt{5}-\sqrt{5}=5\sqrt{5}\).
- \(2\sqrt{27}-\sqrt{12}=2\cdot3\sqrt{3}-2\sqrt{3}=6\sqrt{3}-2\sqrt{3}=4\sqrt{3}\).
- \(5\sqrt{8}+\frac{1}{2}\sqrt{2}-2\sqrt{18}=5\cdot2\sqrt{2}+\frac{1}{2}\sqrt{2}-2\cdot3\sqrt{2}=\left(10+\frac{1}{2}-6\right)\sqrt{2}=\frac{9}{2}\sqrt{2}\).
Ответ: 1) \(5\sqrt{5}\); 3) \(4\sqrt{3}\); 5) \(\frac{9}{2}\sqrt{2}\).
