Ответ:
- \(\dfrac{x^2-4x+4}{x^2-2x}=\dfrac{(x-2)^2}{x(x-2)}=\dfrac{x-2}{x}\).
- \(\dfrac{3y^2+24y}{y^2+16y+64}=\dfrac{3y(y+8)}{(y+8)^2}=\dfrac{3y}{y+8}\).
- \(\dfrac{a^2+a+1}{a^3-1}=\dfrac{a^2+a+1}{(a-1)(a^2+a+1)}=\dfrac{1}{a-1}\).
- \(\dfrac{b+2}{b^3+8}=\dfrac{b+2}{(b+2)(b^2-2b+4)}=\dfrac{1}{b^2-2b+4}\).
Ответ: а) \(\dfrac{x-2}{x}\); б) \(\dfrac{3y}{y+8}\); в) \(\dfrac{1}{a-1}\); г) \(\dfrac{1}{b^2-2b+4}\).
