Ответ:
- \(28-\frac{65}{42}\cdot\frac{40}{13}+\frac{17}{8}\cdot\frac{80}{51}=28-\frac{100}{21}+\frac{10}{3}=\frac{186}{7}\).
- \(\left(\frac{53}{10}-\frac{19}{5}\cdot\frac{13}{38}\right)\cdot\frac{5}{84}+\frac{25}{12}\cdot\frac{4}{15}=4\cdot\frac{5}{84}+\frac{5}{9}=\frac{50}{63}\).
- \(\left(\frac{10}{3}\right)^2-\frac{45}{8}\cdot\frac{12}{5}=\frac{100}{9}-\frac{27}{2}=-\frac{43}{18}\).
- \(\left(\frac{25}{60}+\frac{39}{60}\right)^2\cdot\frac{45}{32}=\left(\frac{16}{15}\right)^2\cdot\frac{45}{32}=\frac{8}{5}\).
Ответ: 1) \(\frac{186}{7}\); 2) \(\frac{50}{63}\); 3) \(-\frac{43}{18}\); 4) \(\frac{8}{5}\).
