4√0,0025 − 10√0,0001; 0,2√1600 − 0,1√4900; 2√(6 1/4) − 3√(1 7/9) + 6√(5 4/9); 1/2√400 − 1/3√900 − 1/6√36; √((9/16) · (4/81) · (36/169)); √((11 14/25) · (5 4/9)); √((64 · 49)/(196 · 324))

1. \(4\sqrt{0.0025}-10\sqrt{0.0001}=4\cdot0.05-10\cdot0.01=0.1\).
2. \(0.2\sqrt{1600}-0.1\sqrt{4900}=0.2\cdot40-0.1\cdot70=1\).
3. \(2\sqrt{6\frac14}-3\sqrt{1\frac79}+6\sqrt{5\frac49}=2\cdot\frac52-3\cdot\frac43+6\cdot\frac73=15\).
4. \(\frac12\sqrt{400}-\frac13\sqrt{900}-\frac16\sqrt{36}=10-10-1=-1\).
5. \(\sqrt{\frac9{16}\cdot\frac4{81}\cdot\frac{36}{169}}=\frac34\cdot\frac29\cdot\frac6{13}=\frac1{13}\).
6. \(\sqrt{11\frac{14}{25}\cdot5\frac49}=\sqrt{\frac{289}{25}\cdot\frac{49}{9}}=\frac{17}{5}\cdot\frac73=\frac{119}{15}\).
7. \(\sqrt{\frac{64\cdot49}{196\cdot324}}=\sqrt{\frac4{81}}=\frac29\).

Ответ: 0,1; 1; 15; −1; 1/13; 119/15; 2/9.