√(4³ + 2³ · 10); √(5³ + 2³ · 7); √64 · √100 · √0,16; 2√0,81 + √0,04; 3√25 − 2/3√81; 1/4√(16/25) + 7√0,09; 6√(1 13/36) − 7√(2 2/49); 1/5√(1 9/16) − 2/3√(1 17/64)

1. \(\sqrt{4^3+2^3\cdot10}=\sqrt{64+80}=\sqrt{144}=12\).
2. \(\sqrt{5^3+2^3\cdot7}=\sqrt{125+56}=\sqrt{181}\).
3. \(\sqrt{64}\cdot\sqrt{100}\cdot\sqrt{0.16}=8\cdot10\cdot0.4=32\).
4. \(2\sqrt{0.81}+\sqrt{0.04}=2\cdot0.9+0.2=2\).
5. \(3\sqrt{25}-\frac{2}{3}\sqrt{81}=3\cdot5-\frac{2}{3}\cdot9=9\).
6. \(\frac14\sqrt{\frac{16}{25}}+7\sqrt{0.09}=\frac14\cdot\frac45+7\cdot0.3=2.3\).
7. \(6\sqrt{1\frac{13}{36}}-7\sqrt{2\frac{2}{49}}=6\cdot\frac76-7\cdot\frac{10}{7}=7-10=-3\).
8. \(\frac15\sqrt{1\frac{9}{16}}-\frac23\sqrt{1\frac{17}{64}}=\frac15\cdot\frac54-\frac23\cdot\frac98=\frac14-\frac34=-\frac12\).

Ответ: 12; √181; 32; 2; 9; 2,3; −3; −1/2.