4) \((81\frac{2}{15}-79,3)\cdot(24,04-22,68)\cdot(1\frac{2}{3}+1\frac{1}{9})\);

1. \(81\frac{2}{15}=81,\overline{13}\), поэтому \(81\frac{2}{15}-79,3=1,\overline{83}=\frac{55}{30}\).
2. \(24,04-22,68=1,36=\frac{34}{25}\).
3. \(1\frac{2}{3}+1\frac{1}{9}=\frac{5}{3}+\frac{10}{9}=\frac{25}{9}\).
4. \(\frac{55}{30}\cdot\frac{34}{25}\cdot\frac{25}{9}=\frac{187}{27}=6\frac{25}{27}\).

Ответ: \(\frac{187}{27}=6\frac{25}{27}\).