6) \((28,24-29,1)\cdot(11,75+30\frac{5}{6}):(40,4-6\frac{1}{3})\);

1. \(28,24-29,1=-0,86=-\frac{43}{50}\).
2. \(11,75+30\frac{5}{6}=\frac{47}{4}+\frac{185}{6}=\frac{511}{12}\).
3. \(40,4-6\frac{1}{3}=\frac{202}{5}-\frac{19}{3}=\frac{511}{15}\).
4. \(-\frac{43}{50}\cdot\frac{511}{12}:\frac{511}{15}=-\frac{43}{50}\cdot\frac{15}{12}=-\frac{43}{40}\).

Ответ: \(-\frac{43}{40}=-1\frac{3}{40}\).