1. \(\frac{27}{20} \cdot (-\frac{5}{9}) = -\frac{27 \cdot 5}{20 \cdot 9} = -\frac{135}{180} = -\frac{3}{4}\)
2. \(\frac{5}{24} \cdot (-\frac{22}{5}) = -\frac{5 \cdot 22}{24 \cdot 5} = -\frac{110}{120} = -\frac{11}{12}\)
3. \(-\frac{3}{4}) - (-\frac{11}{12}) = -\frac{3}{4} + \frac{11}{12} = \frac{-3 \cdot 3 + 11}{12} = \frac{-9 + 11}{12} = \frac{2}{12} = \frac{1}{6}\)
Ответ: \(\frac{1}{6}\)