Решение:
- A) 2,8-a = -2,8
\( -a = -2,8 - 2,8 \)
\( -a = -5,6 \)
\( a = 5,6 \) - Б) 8х-12=3х+8
\( 8x - 3x = 8 + 12 \)
\( 5x = 20 \)
\( x = 4 \) - B) 0,8y+1,2=0,4y-2,8
\( 0,8y - 0,4y = -2,8 - 1,2 \)
\( 0,4y = -4 \)
\( y = -\frac{4}{0,4} = -10 \) - Г) \( 3\frac{2}{9}x-2\frac{5}{12}=2\frac{1}{3}x-1\frac{3}{4} \)
\( \frac{29}{9}x - \frac{29}{12} = \frac{7}{3}x - \frac{7}{4} \)
\( \frac{29}{9}x - \frac{7}{3}x = \frac{29}{12} - \frac{7}{4} \)
\( \frac{29}{9}x - \frac{21}{9}x = \frac{29}{12} - \frac{21}{12} \)
\( \frac{8}{9}x = \frac{8}{12} \)
\( \frac{8}{9}x = \frac{2}{3} \)
\( x = \frac{2}{3} \cdot \frac{9}{8} \)
\( x = \frac{18}{24} = \frac{3}{4} \) - Д) 3х-17=8х+18
\( 3x - 8x = 18 + 17 \)
\( -5x = 35 \)
\( x = -7 \) - E) 0,6y+2,3=0,4y-1,7
\( 0,6y - 0,4y = -1,7 - 2,3 \)
\( 0,2y = -4 \)
\( y = -\frac{4}{0,2} = -20 \) - Ë) \( 3,25x+3\frac{5}{14}=\frac{3}{12}x+4\frac{5}{7} \)
\( \frac{13}{4}x + \frac{47}{14} = \frac{1}{4}x + \frac{33}{7} \)
\( \frac{13}{4}x - \frac{1}{4}x = \frac{33}{7} - \frac{47}{14} \)
\( \frac{12}{4}x = \frac{66}{14} - \frac{47}{14} \)
\( 3x = \frac{19}{14} \)
\( x = \frac{19}{14 \cdot 3} = \frac{19}{42} \) - 3) 7x-14+5x=12-8x+4x
\( 12x - 14 = 12 - 4x \)
\( 12x + 4x = 12 + 14 \)
\( 16x = 26 \)
\( x = \frac{26}{16} = \frac{13}{8} \) - И) 0,4х-1,6=0,9x+2,3
\( 0,4x - 0,9x = 2,3 + 1,6 \)
\( -0,5x = 3,9 \)
\( x = -\frac{3,9}{0,5} = -7,8 \) - K) \( \frac{1}{7}x-15=1+x \)
\( \frac{1}{7}x - x = 1 + 15 \)
\( \frac{1}{7}x - \frac{7}{7}x = 16 \)
\( -\frac{6}{7}x = 16 \)
\( x = 16 \cdot \left(-\frac{7}{6}\right) \)
\( x = -\frac{112}{6} = -\frac{56}{3} \) - Ж) 7х-13=4x-5
\( 7x - 4x = 13 - 5 \)
\( 3x = 8 \)
\( x = \frac{8}{3} \) - Л) 57x-1=1+17x
\( 57x - 17x = 1 + 1 \)
\( 40x = 2 \)
\( x = \frac{2}{40} = \frac{1}{20} = 0,05 \) - M) 18x-19=19x-18
\( 18x - 19x = -18 + 19 \)
\( -x = 1 \)
\( x = -1 \) - H) x+2,3x-4,4=4,4x-2,3
\( 3,3x - 4,4 = 4,4x - 2,3 \)
\( 3,3x - 4,4x = -2,3 + 4,4 \)
\( -1,1x = 2,1 \)
\( x = -\frac{2,1}{1,1} = -\frac{21}{11} \) - Й) \( \frac{x}{4}-12=13-\frac{x}{3} \)
\( \frac{x}{4} + \frac{x}{3} = 13 + 12 \)
\( \frac{3x+4x}{12} = 25 \)
\( \frac{7x}{12} = 25 \)
\( x = 25 \cdot \frac{12}{7} = \frac{300}{7} \)
Ответ: A) 5,6; Б) 4; B) -10; Г) \( \frac{3}{4} \); Д) -7; E) -20; Ë) \( \frac{19}{42} \); 3) \( \frac{13}{8} \); И) -7,8; K) -\( \frac{56}{3} \); Ж) \( \frac{8}{3} \); Л) 0,05; M) -1; H) -\( \frac{21}{11} \); Й) \( \frac{300}{7} \).