5) 3 · 7/15 − 5 1/2 · 7/9 + 1 7/48 · 2 2/11 − 2/5 · 6 5/9

\(3\cdot\frac{7}{15}=\frac{7}{5}\).

\(5\frac{1}{2}\cdot\frac{7}{9}=\frac{11}{2}\cdot\frac{7}{9}=\frac{77}{18}\).

\(1\frac{7}{48}\cdot2\frac{2}{11}=\frac{55}{48}\cdot\frac{24}{11}=\frac{5}{2}\).

\(\frac{2}{5}\cdot6\frac{5}{9}=\frac{2}{5}\cdot\frac{59}{9}=\frac{118}{45}\).

\(\frac{7}{5}-\frac{77}{18}+\frac{5}{2}-\frac{118}{45}=-3\).

Ответ: \(-3\).