7) (1 11/24 + 13/36) · 1 11/25 − 8/15 · 9/16

\(1\frac{11}{24}+\frac{13}{36}=\frac{35}{24}+\frac{13}{36}=\frac{105+26}{72}=\frac{131}{72}\).

\(1\frac{11}{25}=\frac{36}{25}\), поэтому \(\frac{131}{72}\cdot\frac{36}{25}=\frac{131}{50}\).

\(\frac{8}{15}\cdot\frac{9}{16}=\frac{3}{10}\).

\(\frac{131}{50}-\frac{3}{10}=\frac{131}{50}-\frac{15}{50}=\frac{116}{50}=\frac{58}{25}=2\frac{8}{25}\).

Ответ: \(2\frac{8}{25}\).