5) 3x² + 13x − 10 = 0

Question

\(D=13^2-4\cdot3\cdot(-10)=169+120=289=17^2\).

\(x=\frac{-13\pm17}{6}\).

\(x_1=\frac{-13+17}{6}=\frac{2}{3}\), \(x_2=\frac{-13-17}{6}=-5\).

Ответ: \(x_1=\frac{2}{3}\), \(x_2=-5\).

Accepted Answer

\(D=13^2-4\cdot3\cdot(-10)=169+120=289=17^2\).

\(x=\frac{-13\pm17}{6}\).

\(x_1=\frac{-13+17}{6}=\frac{2}{3}\), \(x_2=\frac{-13-17}{6}=-5\).

Ответ: \(x_1=\frac{2}{3}\), \(x_2=-5\).