Ответ:
1)
\[9\frac{1}{4}\cdot8-1\frac{2}{3}\cdot5\frac{1}{2}-2\frac{4}{5}\cdot2\frac{11}{12}\]
\[=\frac{37}{4}\cdot8-\frac{5}{3}\cdot\frac{11}{2}-\frac{14}{5}\cdot\frac{35}{12}\]
\[=74-\frac{55}{6}-\frac{49}{6}=74-\frac{104}{6}=\frac{170}{3}=56\frac{2}{3}.\]
2)
\[2\frac{1}{22}\cdot3\frac{2}{3}-\left(2\frac{5}{6}+3\frac{5}{6}\cdot\frac{7}{23}\right)\cdot\frac{3}{5}\]
\[=\frac{45}{22}\cdot\frac{11}{3}-\left(\frac{17}{6}+\frac{23}{6}\cdot\frac{7}{23}\right)\cdot\frac{3}{5}\]
\[=\frac{15}{2}-\left(\frac{17}{6}+\frac{7}{6}\right)\cdot\frac{3}{5}=\frac{15}{2}-4\cdot\frac{3}{5}=\frac{15}{2}-\frac{12}{5}=\frac{51}{10}=5\frac{1}{10}.\]
Ответ: 1) \(56\frac{2}{3}\); 2) \(5\frac{1}{10}\).
