Ответ:

1) \(a:b-ab=(-0.5):\frac{2}{3}-(-0.5)\cdot\frac{2}{3}=-\frac{3}{4}+\frac{1}{3}=-\frac{5}{12}\).

2) \(\frac{b+c}{b-c}=\frac{\frac{2}{7}-\frac{4}{9}}{\frac{2}{7}+\frac{4}{9}}=\frac{-\frac{10}{63}}{\frac{46}{63}}=-\frac{5}{23}\).

3) \(\frac{x^2+y^2}{x-y}=\frac{(-0.3)^2+(-0.4)^2}{-0.3-(-0.4)}=\frac{0.09+0.16}{0.1}=2.5\).

Ответ: 1) −5/12; 2) −5/23; 3) 2,5.