Ответ:

Решение:

  1. \(\frac{\sqrt{25a^8}\cdot \sqrt{9b^5}}{\sqrt{a^4b^5}} = \sqrt{\frac{25a^8 \cdot 9b^5}{a^4b^5}} = \sqrt{25a^4 \cdot 9} = 5a^2 \cdot 3 = 15a^2 = 15 \cdot 7^2 = 15 \cdot 49 = 735\)
  2. \(\frac{\sqrt{25a^5}\cdot \sqrt{36b^6}}{\sqrt{a^5b^4}} = \sqrt{\frac{25a^5 \cdot 36b^6}{a^5b^4}} = \sqrt{25 \cdot 36b^2} = 5 \cdot 6b = 30b = 30 \cdot 9 = 270\)
  3. \(\frac{\sqrt{4a^{11}}\cdot \sqrt{9b^4}}{\sqrt{a^7b^4}} = \sqrt{\frac{4a^{11} \cdot 9b^4}{a^7b^4}} = \sqrt{4a^4 \cdot 9} = 2a^2 \cdot 3 = 6a^2 = 6 \cdot 7^2 = 6 \cdot 49 = 294\)
  4. \(\frac{\sqrt{25a^9}\cdot \sqrt{16b^8}}{\sqrt{a^5b^8}} = \sqrt{\frac{25a^9 \cdot 16b^8}{a^5b^8}} = \sqrt{25a^4 \cdot 16} = 5a^2 \cdot 4 = 20a^2 = 20 \cdot 4^2 = 20 \cdot 16 = 320\)
  5. \(\frac{\sqrt{4a^6}\cdot \sqrt{25b^7}}{\sqrt{a^2b^7}} = \sqrt{\frac{4a^6 \cdot 25b^7}{a^2b^7}} = \sqrt{4a^4 \cdot 25} = 2a^2 \cdot 5 = 10a^2 = 10 \cdot 9^2 = 10 \cdot 81 = 810\)

Ответ: 5.1. 735, 5.2. 270, 5.3. 294, 5.4. 320, 5.5. 810.