52. 6¹⁰ : (2⁵·3⁴)

\(6^{10}=2^{10}\cdot3^{10}\). Bo‘lganda \(2^{10-5}\cdot3^{10-4}=2^5\cdot3^6\) hosil bo‘ladi.

Bo‘luvchilar soni: \((5+1)(6+1)=6\cdot7=42\).

Javob: 42 ta.