53. (2¹⁰·3¹²) : (4⁴·27³)

\(4^4=2^8\), \(27^3=3^9\). Shuning uchun bo‘linma \(2^{10-8}\cdot3^{12-9}=2^2\cdot3^3\).

Bo‘luvchilar soni: \((2+1)(3+1)=3\cdot4=12\).

Javob: 12 ta.