Ответ:
а) \(\frac{4}{9}+\frac{7}{9}-\frac{1}{9}=\frac{10}{9}=1\frac{1}{9}\).
б) \(\frac{6}{7}-\left(\frac{5}{7}-\frac{1}{7}\right)=\frac{6}{7}-\frac{4}{7}=\frac{2}{7}\).
в) \(5\frac{6}{39}+4\frac{7}{78}=5\frac{12}{78}+4\frac{7}{78}=9\frac{19}{78}\).
г) \(7\frac{13}{15}-3\frac{11}{30}=7\frac{26}{30}-3\frac{11}{30}=4\frac{15}{30}=4\frac{1}{2}\).
д) \(\frac{7}{8}\cdot\frac{4}{35}\cdot\frac{10}{9}=\frac{1}{10}\cdot\frac{10}{9}=\frac{1}{9}\).
е) \(\left(\frac{1}{2}:\frac{3}{4}-\frac{4}{9}\right)\cdot\frac{5}{8}=\left(\frac{2}{3}-\frac{4}{9}\right)\cdot\frac{5}{8}=\frac{2}{9}\cdot\frac{5}{8}=\frac{5}{36}\).
Ответ: а) \(1\frac{1}{9}\); б) \(\frac{2}{7}\); в) \(9\frac{19}{78}\); г) \(4\frac{1}{2}\); д) \(\frac{1}{9}\); е) \(\frac{5}{36}\).
