Ответ:
- \(\dfrac{2x-3y}{4xy}+\dfrac{11y-2x}{4xy}=\dfrac{2x-3y+11y-2x}{4xy}=\dfrac{8y}{4xy}=\dfrac2x\).
- \(\dfrac{5a+b^5}{8b}-\dfrac{5a-7b^5}{8b}=\dfrac{5a+b^5-5a+7b^5}{8b}=\dfrac{8b^5}{8b}=b^4\).
- \(\dfrac{a-2}{8a}+\dfrac{2a+5}{8a}-\dfrac{3-a}{8a}=\dfrac{a-2+2a+5-3+a}{8a}=\dfrac{4a}{8a}=\dfrac12\).
- \(\dfrac{11a-2b}{4a}+\dfrac{2a-3b}{4a}-\dfrac{a-b}{4a}=\dfrac{11a-2b+2a-3b-a+b}{4a}=\dfrac{12a-4b}{4a}=\dfrac{3a-b}{a}\).
Ответ: а) \(\dfrac2x\); б) \(b^4\); в) \(\dfrac12\); г) \(\dfrac{3a-b}{a}\).
