Ответ:
- \(\dfrac{17-12x}{x}-\dfrac{10-x}{x}=\dfrac{17-12x-10+x}{x}=\dfrac{7-11x}{x}\).
- \(\dfrac{12p-1}{3p^2}-\dfrac{1-3p}{3p^2}=\dfrac{12p-1-1+3p}{3p^2}=\dfrac{15p-2}{3p^2}\).
- \(\dfrac{6y-3}{5y}-\dfrac{y+2}{5y}=\dfrac{6y-3-y-2}{5y}=\dfrac{5y-5}{5y}=\dfrac{y-1}{y}\).
- \(\dfrac{3p-q}{5p}-\dfrac{2p+6q}{5p}+\dfrac{p-4q}{5p}=\dfrac{3p-q-2p-6q+p-4q}{5p}=\dfrac{2p-11q}{5p}\).
- \(\dfrac{5c-2d}{4c}-\dfrac{3d}{4c}+\dfrac{d-5c}{4c}=\dfrac{5c-2d-3d+d-5c}{4c}=-\dfrac{4d}{4c}=-\dfrac dc\).
- \(\dfrac{2a}{b}-\dfrac{1-6a}{b}+\dfrac{13-8a}{b}=\dfrac{2a-1+6a+13-8a}{b}=\dfrac{12}{b}\).
Ответ: а) \(\dfrac{7-11x}{x}\); б) \(\dfrac{15p-2}{3p^2}\); в) \(\dfrac{y-1}{y}\); г) \(\dfrac{2p-11q}{5p}\); д) \(-\dfrac dc\); е) \(\dfrac{12}{b}\).
