Ответ:
а) \(6\frac{1}{3}-8=\frac{19}{3}-\frac{24}{3}=-\frac{5}{3}=-1\frac{2}{3}\).
б) \(-2\frac{2}{7}+\frac{8}{5}=-\frac{16}{7}+\frac{8}{5}=\frac{-80+56}{35}=-\frac{24}{35}\).
в) \(6\frac{1}{8}\cdot6\frac{1}{4}=\frac{49}{8}\cdot\frac{25}{4}=\frac{1225}{32}=38\frac{9}{32}\).
г) \(\frac{8}{3}\cdot1\frac{9}{16}=\frac{8}{3}\cdot\frac{25}{16}=\frac{25}{6}=4\frac{1}{6}\).
д) \(\frac{1}{12}\cdot(-6)=-\frac{1}{2}\).
е) \(-3\frac{2}{9}\cdot3=-\frac{29}{9}\cdot3=-\frac{29}{3}=-9\frac{2}{3}\).
ж) \(\frac{4}{7}\cdot(-49)=-28\).
з) \(-16:\left(-\frac{4}{5}\right)=-16\cdot\left(-\frac{5}{4}\right)=20\).
и) \(-3\frac{1}{2}\cdot\left(-1\frac{3}{7}\right)=-\frac{7}{2}\cdot\left(-\frac{10}{7}\right)=5\).
Ответ: а) −1 2/3; б) −24/35; в) 38 9/32; г) 4 1/6; д) −1/2; е) −9 2/3; ж) −28; з) 20; и) 5.
