№6. Вычислите: \(\frac{2}{7}+\frac{6}{14}\); а) \(2-\frac{5}{7}\); б) \(4\frac{3}{15}+5\frac{7}{30}\); в) \(12\frac{4}{7}-\frac{11}{14}\); г) \(5\frac{7}{18}+3\frac{5}{6}\).

1. \(\frac{2}{7}+\frac{6}{14}=\frac{4}{14}+\frac{6}{14}=\frac{10}{14}=\frac{5}{7}\).
2. а) \(2-\frac{5}{7}=1+\frac{2}{7}\).
3. б) \(4\frac{3}{15}+5\frac{7}{30}=9+\frac{6}{30}+\frac{7}{30}=9\frac{13}{30}\).
4. в) \(12\frac{4}{7}-\frac{11}{14}=11+\frac{8}{14}-\frac{11}{14}=10\frac{11}{14}\).
5. г) \(5\frac{7}{18}+3\frac{5}{6}=8+\frac{7}{18}+\frac{15}{18}=9\frac{2}{18}=9\frac{1}{9}\).

Ответ: \(\frac{5}{7}\); а) \(1\frac{2}{7}\); б) \(9\frac{13}{30}\); в) \(10\frac{11}{14}\); г) \(9\frac{1}{9}\).