\((7-4\frac{3}{4})\cdot1\frac{1}{3}+(6-4\frac{2}{5}):1\frac{1}{3}\)

\((7-4\frac{3}{4})\cdot1\frac{1}{3}=\frac{9}{4}\cdot\frac{4}{3}=3\).

\((6-4\frac{2}{5}):1\frac{1}{3}=\frac{8}{5}:\frac{4}{3}=\frac{6}{5}\).

\(3+\frac{6}{5}=\frac{21}{5}\).

Ответ: \(\frac{21}{5}\).