7) \(\(\sqrt{63}\)-4\(\sqrt{28}\)+\(\sqrt{700}\)=

\(\sqrt{63}=3\sqrt7\), \(\sqrt{28}=2\sqrt7\), \(\sqrt{700}=10\sqrt7\).

\(3\sqrt7-4\cdot2\sqrt7+10\sqrt7=(3-8+10)\sqrt7=5\sqrt7\).

Ответ: \(5\sqrt7\).