Ответ:
Қайталанбайтын алмастырулар үшін \(P_n=n!\).
- \(P_4=4!=24\).
- \(P_6=6!=720\).
- \(\dfrac{P_7}{P_5}=\dfrac{7!}{5!}=7\cdot6=42\).
- \(\dfrac{P_6}{P_8}=\dfrac{6!}{8!}=\dfrac{1}{8\cdot7}=\dfrac{1}{56}\).
- \(\dfrac{P_8}{P_7}+\dfrac{P_5}{P_6}=8+\dfrac{1}{6}=\dfrac{49}{6}\).
- \(\dfrac{P_9}{P_7}-\dfrac{P_7}{P_5}=9\cdot8-7\cdot6=72-42=30\).
Жауабы: 24; 720; 42; \(\dfrac{1}{56}\); \(\dfrac{49}{6}\); 30.
