Ответ:

Сократим дроби: \(\frac{21}{63}=\frac{1}{3}\), \(\frac{10}{50}=\frac{1}{5}\), \(\frac{22}{132}=\frac{1}{6}\).

\(\frac{1}{3}-\frac{1}{5}+\frac{1}{6}=\frac{10}{30}-\frac{6}{30}+\frac{5}{30}=\frac{9}{30}=\frac{3}{10}\).

Ответ: \(\frac{3}{10}\).