Ответ:

  1. \(\dfrac{2^{22}-2^2}{7\cdot2^2}=\dfrac{2^2(2^{20}-1)}{7\cdot2^2}=\dfrac{2^{20}-1}{7}=\dfrac{1\,048\,575}{7}=149\,796\dfrac{3}{7}\).
  2. \(\dfrac{2\cdot5^{10}-5^{11}}{6\cdot5^{11}}=\dfrac{5^{10}(2-5)}{6\cdot5^{11}}=-\dfrac{3}{30}=-\dfrac{1}{10}\).
  3. \(\dfrac{3^{12}+3^{10}}{3^{10}}=3^2+1=9+1=10\).
  4. \(\dfrac{5^8+5^6}{2\cdot5^6}=\dfrac{5^6(5^2+1)}{2\cdot5^6}=\dfrac{25+1}{2}=13\).