Решение:
- \(1-\frac{1}{4} = \frac{4}{4}-\frac{1}{4} = \frac{3}{4}\)
- \(1+\frac{1}{5} = \frac{5}{5}+\frac{1}{5} = \frac{6}{5}\)
- \(7-\frac{3}{8} = \frac{56}{8}-\frac{3}{8} = \frac{53}{8}\)
- \(4-\frac{3}{4} = \frac{16}{4}-\frac{3}{4} = \frac{13}{4}\)
Ответ: а) $$\frac{3}{4}$$; б) $$\frac{6}{5}$$; в) $$\frac{53}{8}$$; г) $$\frac{13}{4}$$.