Ответ:

Используем правило: \(a\frac{b}{c}=\frac{ac+b}{c}\).
  1. \(1\frac{2}{5}=\frac{1\cdot5+2}{5}=\frac{7}{5}\);
  2. \(3\frac{8}{11}=\frac{3\cdot11+8}{11}=\frac{41}{11}\);
  3. \(2\frac{3}{11}=\frac{2\cdot11+3}{11}=\frac{25}{11}\);
  4. \(8\frac{11}{15}=\frac{8\cdot15+11}{15}=\frac{131}{15}\);
  5. \(9\frac{1}{20}=\frac{9\cdot20+1}{20}=\frac{181}{20}\).

Ответ: \(\frac75;\ \frac{41}{11};\ \frac{25}{11};\ \frac{131}{15};\ \frac{181}{20}\).