A) 10 − (3 − 2/5 − 5/18) + 12 · (1 + 5/6 + 5/4)

Решение:

\( 10 - (3 - \frac{2}{5} - \frac{5}{18}) + 12 \cdot (1 + \frac{5}{6} + \frac{5}{4}) \)

1. \( 3 - \frac{2}{5} - \frac{5}{18} = \frac{3 \cdot 90}{90} - \frac{2 \cdot 18}{90} - \frac{5 \cdot 5}{90} = \frac{270 - 36 - 25}{90} = \frac{209}{90} \)
2. \( 1 + \frac{5}{6} + \frac{5}{4} = \frac{12}{12} + \frac{10}{12} + \frac{15}{12} = \frac{37}{12} \)
3. \( 10 - \frac{209}{90} + 12 \cdot \frac{37}{12} = 10 - \frac{209}{90} + 37 = 47 - \frac{209}{90} = \frac{47 \cdot 90 - 209}{90} = \frac{4230 - 209}{90} = \frac{4021}{90} \)

Ответ: \( \frac{4021}{90} \)