Решение:
\( \frac{3}{8} + 5 + 4 \cdot \frac{1}{2} - \frac{1}{6} \cdot \frac{1}{10} - \frac{9}{20} - 6 \)
- \( 4 \cdot \frac{1}{2} = 2 \)
- \( \frac{1}{6} \cdot \frac{1}{10} = \frac{1}{60} \)
- \( \frac{3}{8} + 5 + 2 - \frac{1}{60} - \frac{9}{20} - 6 = \frac{3}{8} + 7 - 6 - \frac{1}{60} - \frac{9}{20} = 1 + \frac{3}{8} - \frac{1}{60} - \frac{9}{20} \)
- \( 1 + \frac{3 \cdot 15}{120} - \frac{1 \cdot 2}{120} - \frac{9 \cdot 6}{120} = 1 + \frac{45 - 2 - 54}{120} = 1 + \frac{-11}{120} = \frac{120 - 11}{120} = \frac{109}{120} \)
Ответ: \( \frac{109}{120} \)