a) 3-1-2-1=23 б) 2-1= д) 11-11= e) 5-= B) 5- г) 10- ж) 13- з) 1-

a) $$3\frac{1}{4}-2\frac{1}{4}=(3-2)+(\frac{1}{4}-\frac{1}{4})=1+0=1$$

б) $$2-\frac{1}{3}=\frac{6}{3}-\frac{1}{3}=\frac{5}{3}=1\frac{2}{3}$$

в) $$5-\frac{3}{4}=\frac{20}{4}-\frac{3}{4}=\frac{17}{4}=4\frac{1}{4}$$

г) $$10-\frac{2}{9}=\frac{90}{9}-\frac{2}{9}=\frac{88}{9}=9\frac{7}{9}$$

д) $$11-\frac{11}{100}=\frac{1100}{100}-\frac{11}{100}=\frac{1089}{100}=10\frac{89}{100}$$

e) $$5-\frac{2}{7}=\frac{35}{7}-\frac{2}{7}=\frac{33}{7}=4\frac{5}{7}$$

ж) $$13-\frac{7}{10}=\frac{130}{10}-\frac{7}{10}=\frac{123}{10}=12\frac{3}{10}$$

з) $$1-\frac{2}{5}=\frac{5}{5}-\frac{2}{5}=\frac{3}{5}$$

Ответ:

a) $$3\frac{1}{4}-2\frac{1}{4}=1$$

б) $$2-\frac{1}{3}=1\frac{2}{3}$$

в) $$5-\frac{3}{4}=4\frac{1}{4}$$

г) $$10-\frac{2}{9}=9\frac{7}{9}$$

д) $$11-\frac{11}{100}=10\frac{89}{100}$$

e) $$5-\frac{2}{7}=4\frac{5}{7}$$

ж) $$13-\frac{7}{10}=12\frac{3}{10}$$

з) $$1-\frac{2}{5}=\frac{3}{5}$$