А10. Решите уравнение

1) $$2-\frac{2x-5}{6}=\frac{3-5x}{4}$$
2) $$2-\frac{2x-5}{6}=\frac{3-5x}{4}$$
3) $$2-\frac{2x-5}{6}=\frac{3-5x}{4}$$
4) $$2-\frac{2x-5}{6}=\frac{3-5x}{4}$$
5) $$2-\frac{2x-5}{6}=\frac{3-5x}{4} \implies \frac{12-(2x-5)}{6}=\frac{3-5x}{4} \implies \frac{17-2x}{6}=\frac{3-5x}{4} \implies 4(17-2x)=6(3-5x) \implies 68-8x=18-30x \implies 22x=-50 \implies x=-\frac{50}{22}=-\frac{25}{11}$$