8) 1 2 3 4 a2b2+ a²b+ ab²+ a2b2 = 5 5 5 5

8) $$\frac{1}{5}a^{2}b^{2} + \frac{2}{5}a^{2}b + \frac{3}{5}ab^{2} + \frac{4}{5}a^{2}b^{2} = \frac{1}{5}a^{2}b^{2} + \frac{4}{5}a^{2}b^{2} + \frac{2}{5}a^{2}b + \frac{3}{5}ab^{2} = \frac{5}{5}a^{2}b^{2} + \frac{2}{5}a^{2}b + \frac{3}{5}ab^{2} = a^{2}b^{2} + \frac{2}{5}a^{2}b + \frac{3}{5}ab^{2}$$

Ответ: $$a^{2}b^{2} + \frac{2}{5}a^{2}b + \frac{3}{5}ab^{2}$$