б) \(\frac{9}{9} + \frac{7}{15} - \frac{1}{18}\) + \(\frac{5}{30}\).

б) \(\frac{9}{9} + \frac{7}{15} - \frac{1}{18}\) + \(\frac{5}{30}\) = 1 + \(\frac{7}{15}\) - \(\frac{1}{18}\) + \(\frac{1}{6}\) = 1 + \(\frac{7 \cdot 6}{15 \cdot 6}\) - \(\frac{1 \cdot 5}{18 \cdot 5}\) + \(\frac{1 \cdot 15}{6 \cdot 15}\) = 1 + \(\frac{42}{90}\) - \(\frac{5}{90}\) + \(\frac{15}{90}\) = 1 + \(\frac{42 - 5 + 15}{90}\) = 1 + \(\frac{52}{90}\) = 1 + \(\frac{26}{45}\) = 1 \(\frac{26}{45}\)

Ответ: 1 \(\frac{26}{45}\)