Б 9) \(\frac{2}{3a}-\frac{3b+4}{3a}\)

\(\frac{2}{3a}-\frac{3b+4}{3a}=\frac{2-3b-4}{3a}=-\frac{3b+2}{3a}\).

Ответ: \(-\frac{3b+2}{3a}\)