2) $$ \frac{7b^4}{9c^5y} : \frac{35b^4c}{18c^4y^2} = \frac{7b^4}{9c^5y} \cdot \frac{18c^4y^2}{35b^4c} = \frac{7b^4 \cdot 18c^4y^2}{9c^5y \cdot 35b^4c} = \frac{7 \cdot 2y}{c^2 \cdot 35} = \frac{2y}{5c^2} $$
Ответ: $$ \frac{2y}{5c^2} $$