д) (3 2/3-2 2/7)⋅2 1/2;

д) Выполним действия по порядку.

1. $$3\frac{2}{3} = \frac{3 \cdot 3 + 2}{3} = \frac{9+2}{3} = \frac{11}{3}$$
2. $$2\frac{2}{7} = \frac{2 \cdot 7 + 2}{7} = \frac{14+2}{7} = \frac{16}{7}$$
3. $$2\frac{1}{2} = \frac{2 \cdot 2 + 1}{2} = \frac{4+1}{2} = \frac{5}{2}$$
4. $$\frac{11}{3} - \frac{16}{7} = \frac{11 \cdot 7}{3 \cdot 7} - \frac{16 \cdot 3}{7 \cdot 3} = \frac{77}{21} - \frac{48}{21} = \frac{77-48}{21} = \frac{29}{21}$$
5. $$\frac{29}{21} \cdot \frac{5}{2} = \frac{29 \cdot 5}{21 \cdot 2} = \frac{145}{42} = 3\frac{19}{42}$$

Ответ: $$3\frac{19}{42}$$